c语言小游戏代码大全

在C语言中，你可以实现各种小游戏。

1. 猜数字游戏

c
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main() {
    int guess, number, attempts = 0;
    
    // 生成随机数
    srand(time(NULL));
    number = rand() % 100 + 1; // 生成1到100的随机数

    printf("欢迎来到猜数字游戏!\n");
    printf("猜一个1到100之间的数字。\n");

    do {
        printf("请输入你的猜测: ");
        scanf("%d", &guess);
        attempts++;

        if (guess > number) {
            printf("太大了！\n");
        } else if (guess < number) {
            printf("太小了！\n");
        } else {
            printf("恭喜你，猜对了！你用了%d次尝试。\n", attempts);
        }
    } while (guess != number);

    return 0;
}

2. 井字棋游戏

c
#include <stdio.h>

// 定义常量
#define SIZE 3

// 初始化游戏板
void initializeBoard(char board[SIZE][SIZE]) {
    for (int i = 0; i < SIZE; i++) {
        for (int j = 0; j < SIZE; j++) {
            board[i][j] = ' ';
        }
    }
}

// 打印游戏板
void printBoard(char board[SIZE][SIZE]) {
    for (int i = 0; i < SIZE; i++) {
        for (int j = 0; j < SIZE; j++) {
            printf("%c", board[i][j]);
            if (j < SIZE - 1) {
                printf(" | ");
            }
        }
        printf("\n");
        if (i < SIZE - 1) {
            printf("---------\n");
        }
    }
    printf("\n");
}

// 检查是否有玩家获胜
int checkWin(char board[SIZE][SIZE], char player) {
    // 检查行和列
    for (int i = 0; i < SIZE; i++) {
        if ((board[i][0] == player && board[i][1] == player && board[i][2] == player) ||
            (board[0][i] == player && board[1][i] == player && board[2][i] == player)) {
            return 1; // 有玩家获胜
        }
    }

    // 检查对角线
    if ((board[0][0] == player && board[1][1] == player && board[2][2] == player) ||
        (board[0][2] == player && board[1][1] == player && board[2][0] == player)) {
        return 1; // 有玩家获胜
    }

    return 0; // 没有玩家获胜
}

int main() {
    char board[SIZE][SIZE];
    int row, col;
    char currentPlayer = 'X';
    int moves = 0;

    initializeBoard(board);

    do {
        printBoard(board);

        // 获取玩家输入
        printf("玩家 %c，请输入行号和列号：", currentPlayer);
        scanf("%d %d", &row, &col);

        // 检查输入的合法性
        if (row < 0 || row >= SIZE || col < 0 || col >= SIZE || board[row][col] != ' ') {
            printf("无效的输入，请重新输入。\n");
            continue;
        }

        // 更新游戏板
        board[row][col] = currentPlayer;
        moves++;

        // 检查是否有玩家获胜
        if (checkWin(board, currentPlayer)) {
            printBoard(board);
            printf("玩家 %c 胜利！\n", currentPlayer);
            break;
        }

        // 切换玩家
        currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';

        // 检查是否平局
        if (moves == SIZE * SIZE) {
            printBoard(board);
            printf("游戏平局！\n");
            break;
        }

    } while (1);

    return 0;
}

这两个例子只是C语言小游戏的开始，你可以根据自己的兴趣和需求进行修改和扩展。希望这些代码能够帮助你入门C语言游戏编程！

3. 俄罗斯方块游戏

c
#include <stdio.h>
#include <stdlib.h>
#include <conio.h>
#include <windows.h>
#define WIDTH 10
#define HEIGHT 20
int board[WIDTH][HEIGHT] = {0};
struct Point {
int x, y;
};
struct Block {
struct Point points[4];
};
// 初始化游戏板
void initializeBoard() {
for (int i = 0; i < WIDTH; i++) {
for (int j = 0; j < HEIGHT; j++) {
board[i][j] = 0;
}
}
}
// 显示游戏板
void displayBoard() {
system("cls");  // 清屏
for (int j = 0; j < HEIGHT; j++) {
for (int i = 0; i < WIDTH; i++) {
if (board[i][j] == 0) {
printf(" .");
} else {
printf(" *");
}
}
printf("\n");
}
}
// 在游戏板上绘制方块
void drawBlock(struct Block block, int value) {
for (int i = 0; i < 4; i++) {
int x = block.points[i].x;
int y = block.points[i].y;
board[x][y] = value;
}
}
// 检查方块是否可以移动
int canMove(struct Block block, int offsetX, int offsetY) {
for (int i = 0; i < 4; i++) {
int x = block.points[i].x + offsetX;
int y = block.points[i].y + offsetY;
// 检查是否越界或与其他方块重叠
if (x < 0 || x >= WIDTH || y < 0 || y >= HEIGHT || board[x][y] != 0) {
return 0;
}
}
return 1;
}
// 移动方块
void moveBlock(struct Block *block, int offsetX, int offsetY) {
for (int i = 0; i < 4; i++) {
block->points[i].x += offsetX;
block->points[i].y += offsetY;
}
}
// 旋转方块
void rotateBlock(struct Block *block) {
int centerX = block->points[1].x;
int centerY = block->points[1].y;
for (int i = 0; i < 4; i++) {
int x = block->points[i].x;
int y = block->points[i].y;
// 使用旋转矩阵进行旋转
int newX = centerX + centerY - y;
int newY = centerY - centerX + x;
block->points[i].x = newX;
block->points[i].y = newY;
}
}
// 主游戏循环
void gameLoop() {
struct Block currentBlock;
int gameover = 0;
int score = 0;
while (!gameover) {
// 生成一个新的方块
currentBlock.points[0].x = WIDTH / 2 - 1;
currentBlock.points[0].y = 0;
currentBlock.points[1].x = WIDTH / 2;
currentBlock.points[1].y = 0;
currentBlock.points[2].x = WIDTH / 2 - 1;
currentBlock.points[2].y = 1;
currentBlock.points[3].x = WIDTH / 2;
currentBlock.points[3].y = 1;
// 游戏循环中的每一帧
while (1) {
displayBoard();
drawBlock(currentBlock, 1);
// 检查用户输入
if (_kbhit()) {
char key = _getch();
switch (key) {
case 'a':
if (canMove(currentBlock, -1, 0)) {
moveBlock(&currentBlock, -1, 0);
}
break;
case 'd':
if (canMove(currentBlock, 1, 0)) {
moveBlock(&currentBlock, 1, 0);
}
break;
case 's':
if (canMove(currentBlock, 0, 1)) {
moveBlock(&currentBlock, 0, 1);
}
break;
case 'w':
struct Block rotatedBlock = currentBlock;
rotateBlock(&rotatedBlock);
if (canMove(rotatedBlock, 0, 0)) {
currentBlock = rotatedBlock;
}
break;
case 'q':
gameover = 1;
break;
}
}
// 检查方块是否能向下移动
if (canMove(currentBlock, 0, 1)) {
moveBlock(&currentBlock, 0, 1);
} else {
// 将方块固定在游戏板上
drawBlock(currentBlock, 1);
// 检查是否有行被填满
for (int y = HEIGHT - 1; y >= 0; y--) {
int rowFull = 1;
for (int x = 0; x < WIDTH; x++) {
if (board[x][y] == 0) {
rowFull = 0;
break;
}
}
// 如果一行被填满，消除该行并增加分数
if (rowFull) {
for (int i = y; i > 0; i--) {
for (int x = 0; x < WIDTH; x++) {
board[x][i] = board[x][i - 1];
}
}
score += 10;
}
}
// 生成新的方块
break;
}
Sleep(100);  // 控制游戏速度
}
}
}
int main() {
initializeBoard();
gameLoop();
return 0;
}

这是一个简单的俄罗斯方块游戏的实现。通过“a”、“d”、“s”和“w”键控制方块的左移、右移、下移和旋转，按“q”键退出游戏。游戏循环中的每一帧显示当前游戏板状态，并在方块无法下移时固定在游戏板上。当一行被填满时，该行消失，玩家得分增加。游戏通过方向键和空格键等输入进行交互。